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Head ofice : #907, Xizi International, Linping ,Hangzhou, Zhejiang,China M:0086136 0051 3715 email: [email protected] www.juntaiplastic.com www.chinambbr.com |
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| Juntai Aeration Volume Calculator | ||||
| Blue block is the design datameter : be filled in Brown: calculate process data Red : last result for your process |
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| 1.Aerobic Tank volume calculation | ||||
| Calculation Formula |  |
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| Design parameters: | ||||
| Qmax | 150 | Daily sewage design flow, m3/d | ||
| So | 400 | Sewage untreated for five days - (BOD5 concentration), mg/l | ||
| Se | 20 | Five days after treatment - (BOD5 concentration), mg/l | ||
| BODSS | 0.12 | Sludge load, kg-BOD/kg·MLSS/day | ||
| MLSS | 4000 | Sludge concentration, mg/l | ||
| Result | 118.75 | M3 | ||
| 2.Denitrification cabinet volume calculation | ||||
| Calculation Formula |  |
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| Design parameters: | ||||
| NIKN | 250 | Concentration of ammonia nitrogen in treated effluent, mg/l | ||
| NETN | 30 | Concentration of ammonia nitrogen in treated effluent, mg/l | ||
| MDNL | 0.5 | Sludge denitrification load, kg-NH3-N/kg·MLSS/day | ||
| MLSS | 3000 | Sludge concentration, mg/l | ||
| Result | 22 | M3 | ||
| 3.Aeration Calculation | ||||
| Calculation Formula |  |
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| Design parameters: | ||||
| Ro2- | 172.35 | Design sewage oxygen demand, kgO2/d | ||
| So- | 400 | Five-day biochemical oxygen demand of influent water, mg/L | ||
| Se- | 20 | Five-day biochemical oxygen demand of effluent, mg/L | ||
| △Xv- | 11.08 | Amount of microorganisms discharged from the oxidation tank to the system, kg/d | ||
| Nk- | 275.00 | Total Kjeldahl nitrogen in influent, mg/L | ||
| Nke- | 45 | Total Kjeldahl nitrogen in effluent, mg/L | ||
| Nt- | 275.00 | Total nitrogen in influent, mg/L | ||
| Noe- | 21 | Amount of nitrate nitrogen in effluent, mg/L | ||
| a- | 1.47 | Carbon equivalent, when the carbonaceous material is measured in terms of five-day biochemical oxygen demand, take 1.47 |
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| b- | 4.57 | Constant, oxygen demand for oxidizing each kilogram of ammonia nitrogen, kgO2/kgN, take 4.57. | ||
| c- | 1.42 | Constant, oxygen content of bacterial cells, taken as 1.42 | ||
| d- | 0.08 | Constant, sludge auto-oxidation rate, taken as 0.08 | ||
| N'- | 2.8 | Average concentration of volatile suspended solids in the mixture (g vss/L) at 70% of the sludge volume | ||
| θ- | 30 | Sludge age, 30d | ||
| Result | 172.3518987 | kgO2/d | ||
| 4. Absolute Pressure Calculation | ||||
| Calculation Formula |  |
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| Design parameters: | ||||
| Pb- | 133040 | Absolute pressure at which the aeration device is located, Pa | ||
| H- | 4.3 | Aeration diffuser gas port at the water depth, m (water depth minus the aeration disc installation height, according to the depth of the tank accounting) |
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| P- | 90900 | Atmospheric pressure, Pa (actual atmospheric pressure at location) | ||
| Result | 133040 | Pa | ||
| 5.Calculation of oxygen content in per cent | ||||
| Calculation Formula |  |
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| Design parameters: | ||||
| Ot- | 16.62% | Percentage of oxygen in the gas escaping from the aeration basin, dimensionless | ||
| EA- | 25% | Transfer coefficient of diffusion device, % oxygen utilisation (value selected with reference to technical parameters provided by SSI manufacturer) |
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| Result | 0.166226913 | |||
| 6.Calculation of average dissolved value | ||||
| Calculation Formula |  |
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| Design parameters: | ||||
| Csm | 8.82 | T℃、Average dissolved value of clear water from the depth of the water under which the actual aeration device is located to the surface of the pool, mg/1TC, |
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| Csw | 8.38 | T℃、Saturated dissolved oxygen on the surface of clear water at actual calculated pressure, mg/1(CS(20)＝9.17mg/L，CS(25)＝8.38mg/L) |
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| T- | 25 | ℃ | ||
| Result | 8.818924806 | mg/L | ||
| 7.Calculation of oxygen demand correction factor | ||||
| Calculation Formula |  |
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| Design parameters: | ||||
| KO- | 1.715 | Oxygen demand correction factor | ||
| Co- | 2 | Remaining dissolved oxygen concentration of mixed liquid, mg/L | ||
| Cs | 9.17 | Saturated dissolved oxygen mass concentration in clear water under standard condition, mg/1 |
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| α- | 0.8 | Transfer efficiency resistance coefficient, the influence of the nature of wastewater on dissolved oxygen, correction factor K1a |
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| Raw domestic sewagea value of about 0.4~0.5 | ||||
| Industrial wastewatera value varies greatly 0.8~0.85 | ||||
| The effect of salts in wastewater on dissolved oxygen, saturated oxygen resistance factor |
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| β- | 0.9 | β value is generally between 0.9~0.97 | ||
| Result | 1.71478688 | |||
| 8.(Calculated on 24h basis) Aeration basin air supply volume Aeration basin air supply volume calculation | ||||
| Calculation Formula |   |
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| Design parameters: | ||||
| Ro | 295.52 | kgO2/d | ||
| Gs | 12.31 | kgO2/h Aeration basin gas supply (24h) | ||
| Gs | 175.91 | m3/h | ||
| Gs | 2.93 | m3/min | ||
| Calculation Formula |  |
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| Design parameters: | ||||
| Gs max | 3.66 | m3/min | ||
| Gs max | 219.88 | m3/h | ||
| 9.Air pressure required for aeration P (relative pressure) | ||||
| Calculation Formula | P＝h1+h2+h3+h4+△h | |||
| Design parameters: | ||||
| h1+h2 | 0.2 | m(Duct length and local resistance) | ||
| h3 | 4.3 | m(Aeration head submergence depth) | ||
| h4 | 0.3 | m(Aerator resistance) | ||
| △h | 0.5 | m(Have a high head of water) | ||
| P | 5.3 | m(Total air pressure0.53kg/m2) | ||
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